Gauss's Law

Which law is used to derive the expression for the electric field between two uniformly charged large parallel sheets with surface charge densities $\sigma$ and $-\sigma$ respectively:

A charge $Q$ is placed at the mouth of a conical flask. The flux of the electric field through the flask is

$4500$ flux lines are going inside an area of ​​a certain volume and $2500$ flux lines are passing through that area are going out. How much charge is there within that field?

The electric field $\overrightarrow{E}=E_{0}y\hat{j}$  acts in the space in which a cylinder of radius $r$ and length $l$ is placed with its curved surfaces parallel to $y‐$axis. The charge inside the volume of cylinder is

Find the flux through the disc.

Assertion: Gauss's law can't be used to calculate electric field near an electric dipole.
Reason: Electric dipole don't have symmetrical charge distribution.

A hollow cylinder has a charge $q$ coulomb within it. If $\varphi$ is the electric flux in units of $\mathrm{Volt} \mathrm{meter}$ associated with the curved surface $\mathrm{B}$, the flux linked with the plane surface $\mathrm{A}$ in units of $\mathrm{Volt} \mathrm{meter}$ will be

The potential (in volts) of a charge distribution is given by

$V\left(z\right)=30-5z^2$ for $\left|z\right|\le 1\mathrm{ }\mathrm{m}$

$V\left(z\right)=35-10\mathrm{ }\left|\mathrm{z}\right|$ for $\left|Z\right|\ge 1\mathrm{ }\mathrm{m}$ .

$V\left(z\right)$ does not depend on $x$ and $y$. If this potential is generated by a constant charge per unit volume ${\mathrm{\rho }}_0$ (in units of ${\mathrm{ϵ}}_0$ ) which is spread over a certain region, then choose the correct statement.

A charge $Q$ is placed at a distance $\raisebox{1ex}{$a$}\!\left/ \!\raisebox{-1ex}{$2$}\right.$ above the centre of a square surface of side length $a$. The electric flux through the square surface due to the charge would be?

Total flux coming out of some closed surface is:

The region between two concentric spheres of radii $\text{'}a\text{'}$ and $\text{'}b\text{'},$ respectively (see figure), has volume charge density $\rho =\frac{A}{r},$ where $A$ is a constant and $r$ is the distance from the centre. At the centre of the spheres is a point charge $Q.$ The value of $A$ such that the electric field in the region between the spheres will be constant, is:

The total flux through the faces of the cube with side of length $\mathrm{\alpha }$ if a charge $\mathrm{q}$ is placed at corner $\mathrm{A}$ of the cube is

A point charge of $1.8 \mathrm{\mu C}$ is at the centre of cubical Gaussian surface$55 \mathrm{cm}$ on edge. What is the net electric flux through the surface?

A ring of radius $R$ having a linear charge density $\lambda$ moves towards a solid imaginary sphere of radius $\frac{R}{2},$ so that the centre of ring passes through the centre of the sphere. The axis of the ring is perpendicular to the line joining the centres of the ring and the sphere. The maximum flux through the sphere in this process is

Flux coming out from a unit positive charge enclosed in air is

A Gaussian sphere encloses an electric dipole within it. The total flux across the sphere is

$q_1,\mathrm{ }{q}_2,\mathrm{ }{q}_3$ and $q_4$ are point charges located at points, as shown in the figure, and $S$ is a spherical Gaussian surface of radius $R$. Which of the following is true, according to the Gauss' law?

The figure shows a closed surface which intersects a conducting sphere. If a positive charge is placed at the point $P$, the flux of the electric field through the closed surface, 

A Gaussian sphere encloses an electric dipole within it. The total flux through the sphere is

Flux coming out from a unit positive charge enclosed in air is